Can You Help My Grandfather ?

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Thanks for dropping by 😉 but does my grandfather actually needs help ?

Emmmm... Read on to find out.

However, before we proceed, i would like to make an announcement and it's that for now the conventional blogging style (of which some may find boring and also common in this community) would be paused. Let's move on to something more fun, like a game. This game(s) however would be interesting, educative and rewarding, and it's also expected to conform with the philosophy of this community (STEM related). So who's ready to play?

In the absence of any response except mine as at the time of writing this - majority carries the vote, let's get on with it. 😎

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Early this morning, my grandfather and I were having a conversation about great men of science, particularly in the 17th century. He seemed to be talking about one that was very amusing to him, this historical figure was amongst the leading experts in horology as at the time. According to my grandfather, when he was younger he so loved reading about certain great men of science that he also kept records of their date of birth and death in his head. But due certain circumstances such as old age, he seemed to have forgotten the year this particular historical figure died and he needs your help remembering this year. Can you help my grandfather figure out this forgotten year. The clues below may be of assistance.

The first three digits of this forgotten year is a number whose square root gives the first two odd numbers.

To get the last digit of this forgotten year, we need to find the last digit of the mathematical operation given below

5^140 (which reads 5 raised to the power of 140)

The last clue isn't as hard as you may think.

Well, if you think the clues presented are too hard, you can try others which has been presented earlier, though not stated explicitly - re-read the article again, especially the part just after the first image of this article and also the image itself.

There's also a price to be awarded, as commanded by my grandfather. A total of 2 hive to be distributed, 1 hive to the first person who provides the answer and the remaining to be shared amongst at most the second three to also provide answers. The answer should be provided at the end of this article in the comment section and it should be provided from now (May 6) till the next three days (May 9).

Disclaimer

Please note that there was never any conversation between me and my grandfather. In fact, i never met any of my grandfathers - they had died before i was born. The conversation presented here is purely a work of fiction. 😂

Lastly, with regards to the riddle presented in my previous article, especially to @thecuriousfool who is curious about the actual answer. The actual answer or rather the answer i was expecting is/was "elastic", though you were very close. Sorry this is coming late from me.

It's here we conclude this episode, have a thoughtful day and see you next time.

Thank you all once again for stopping by to read my jargons and also thank you @juecoree, @lemouth and the @Steemstem team for your valuable supports.

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14 comments
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I have to come back again later to think of the answer for this challenge.

For the main time, here's a !1UP for engaging the community to think hard. 😁
Keep it up man.

Ohh, btw, I don't see any CTP tag related contents in your article. Kindly use it for affiliate marketing or entrepreneurship related contents only. Hope you understand. 🙂

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For the main time, here's a !1UP for engaging the community to think hard. 😁
Keep it up man.

Thanks

Ohh, btw, I don't see any CTP tag related contents in your article. Kindly use it for affiliate marketing or entrepreneurship related contents only. Hope you understand. 🙂

Ohh, i see. Ok

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You have received a 1UP from @thecuriousfool!

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a number whose square root gives the first two odd numbers.

All powers of 5 end in 5 but I have no idea how a square root gives a number. I was thinking maybe 13 * 13 = 169 . I did not find the name of a famous scientist clockmaker born in 1695.

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All powers of 5 end in 5

I think that needs a tiny proof. I would use induction but maybe it can be done simpler.

f(k) = 5^k for k=1 ends in a 5.
assume f(n) ends in a 5
then f(n+1) ends in a 5 since f(n+1) = 5 * f(n) with the final digit of f(n) ending in a 5.

But perhaps I am overcomplicating stuff.

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(Edited)

I did not find the name of a famous scientist clockmaker born in 1695.

Not born but death, you probably didn't read the article well.

But due certain circumstances such as old age, he seemed to have forgotten the year this particular historical figure died

You seem not too confident about your answer. Make up your mind

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Thank you. I was tired when I read the question and clearly misread it.

Asking for the last digit of a random power of five was a fun twist to a question. I probably shouldn't be curating after midnight.

The real kicker was that you spoke about the 17th century. A person born in 1695 is unlikely to have much influence in the 1600s.

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Thank you for your witness vote!
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This was a nice game to do during the train trip to the institute. Me and my son like riddles very much, and I may actually ask him to solve that one. He has the necessary skills to do it.

So, to come back to the point. I can definitely help your virtual grand-father to virtually remember that Huygens died in 1695. Unfortunately, I was not the first to find out the answer...

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Ooh... So you are around, interesting.

Me and my son like riddles very much, and I may actually ask him to solve that one. He has the necessary skills to do it.

What's that phrase again 🤔. I remember now "like father like son". What an interesting son you have there but i don't envy you - I'm somebody's son 😁.

So, to come back to the point. I can definitely help your virtual grand-father to virtually remember that Huygens died in 1695. Unfortunately, I was not the first to find out the answer...

You seem so confident, i like that but are you really really sure that your answer is correct ?

I guess we would have to find out when i release the result probably in a forthcoming article.

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Ooh... So you are around, interesting.

yes yes, I am back. I had a very busy offline period (end of the semester + visiting collaborators, as mentioned in my next-to-last post) but now it is almost done. I am mostly back and ready to engage again with everybody.

What's that phrase again 🤔. I remember now "like father like son". What an interesting son you have there but i don't envy you - I'm somebody's son 😁.

In fact, my son and I are very much alike. Whereas this holds for the good sides, this also holds for the not so good ones (the features in me I would like to change without any success :D ). But this is fine.

You seem so confident, i like that but are you really really sure that your answer is correct ?
I guess we would have to find out when i release the result probably in a forthcoming article.

I can never be 100% sure, but it sounded correct for me, especially with the picture of the clock. I would be very happy to read that I am wrong (I will check out the new post later today) :)

Have a great day!

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